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Icom IC- 22S mods


NOTICE: TO ALL CONCERNED Certain text files and messages contained on this site deal with activities and devices which would be in violation of various Federal, State, and local laws if actually carried out or constructed. The webmasters of this site do not advocate the breaking of any law. Our text files and message bases are for informational purposes only. We recommend that you contact your local law enforcement officials before undertaking any project based upon any information obtained from this or any other web site. We do not guarantee that any of the information contained on this system is correct, workable, or factual. We are not responsible for, nor do we assume any liability for, damages resulting from the use of any information on this site.
IC22S.3
BAND SEGMENT MODIFICATION:

The normal frequency coverage of the IC-22S (with X1=7.680 MHz) is 144.390 to
148.215 MHz, a range of 3.825 MHz (Fmax - Fmin), by 15 KHz steps. The
frequency segment covered by the IC-22S is settled by Crystal X2 (near X1 on
PLL board). Its normal frequency is: 44.563 333 MHz. The lowest frequency
(Binary code 00) and the highest frequency (binary code 255) covered by the
radio with a given crystal (X2) is calculated this way:

Fmin. = (Xtal freq. x 3) + 10.7 MHz
Fmax. = (Xtal freq. x 3) + 10.7 MHz + (RANGE)

RANGE = (X1 / 2) - (X1 / 512)

Example:
Fmin=(44.563 333 MHz x3) + 10.7 MHz=144.390 MHz
Fmax=(44.563 333 MHz x3) + 10.7 MHz +((7.68 MHz/2)-(7.68 MHz/512))=148.215 MHz

As I said before, the normal coverage of the IC-22S is 144.390 to 148.215 MHz
(With X1=7.680 MHz). The 215 KHz Higher than 148.000 are useless and limits
coverage in the low portion of the 2 meter band. Changing X2 by a 44.488 333
MHz crystal will make the IC-22S covering from 144.165 to 147.990 MHz (15 KHz
steps).
Fmin = (44.488 333 x 3) + 10.7 = 144.165 MHz
Fmax = (44.488 333 x 3) + 10.7 + ((7.68/2)-(7.68/512)) = 147.990 MHz

An interesting modification is to change X1 for a 5.120 MHz crystal, allowing
a 10 KHz step, and change X2 for two appropriate crystal, each one allowing
2 MHz coverage.

With X1=5.120 MHz, replacing X2 by a 44.923 333 MHz crystal will give the
following coverage:

Fmin = (44.923 333 x 3) + 10.7 = 145.470 MHz

Fmax = (44.923 333 x 3) + 10.7 + ((5.12/2)-(5.12/512)) = 148.020 MHz

With X1=5.120 MHz, replacing X2 by a 44.250 000 MHz crystal will give the
following coverage:

Fmin = (44.250 000 x 3) + 10.7 = 143.450 MHz

Fmax = (44.250 000 x 3) + 10.7 + ((5.12/2)-(5.12/512)) = 146.000 MHz

These two crystals could be installed with a switching device, to use one at a
time. This allows fuull coverage of the 2 meter amateur band (144-148 MHz),
in 10 KHz segments. Local oscillator can be slightly detuned to allow
operation on 5 khz steps (146.745 MHz, example). I have not worked on it yet.
If you do it successfully, let me know!
 
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